Re: Ordering vertices on an inclined line
Hello
A great solution because it is simpler. You don't have to make any lines at all.
After all, it is already there - formed by the first and last vertex ... Until I am surprised that it did not occur to me.
The only thing left to ask is why such a simple solution was not introduced in earlier versions of AC 3 D? Program users did not ask about it?
greetings
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